| Author |
Comment/Response |
igor igel
|
 06/22/12 09:13am
In Response To 'Re: Re: Re: Re: Limit returns unevaluated input'
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Oh infinity...
Sorry in the second formula of my post (the evaluated first formula) a 1/n in the exponent somehow got lost.
The following formula is the correct one, when trying to calculate the limit n->infinity mathematica gives, no matter which assmuptions are used, the input as an output.
By the way does it make any difference whether "&&" or "," connects different assumptions?
(1/Sqrt[2 \[Pi]])((E^(-(((b0^2 - b1^2) (m0 -
m1) (-b1^2 (m0 + m1 (-1 + n) + 3 m0 n - 4 n x) +
b0^2 (m0 - m1 + m0 n + 3 m1 n - 4 n x)) -
2 n (b1^2 (m0 - x) + b0^2 (-m1 + x))^2 PolyGamma[0, (
b0^2 + b1^2 (-1 + n))/(b0^2 - b1^2)] +
2 n (b1^2 (m0 - x) + b0^2 (-m1 + x))^2 PolyGamma[
0, (-b1^2 + b0^2 (1 + n))/(b0^2 - b1^2)])/(
4 (b0 - b1)^3 (b0 + b1)^3)))/(Sqrt[((b0^2 - b1^2)/n)^
n Pochhammer[1 + (b1^2 n)/(b0^2 - b1^2), n]]))^((1/n)))
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