| Author |
Comment/Response |
Michael
|
 06/29/12 9:06pm
Your function does not appear to be a PDF -- the integral (over all x, or x, n) is greater than 1. In fact it is very close to
In[86]:= PDF[NormalDistribution[0, \[Pi]^(1/4) \[Sigma]], x]
Out[86]= E^(-(x^2/(2 Sqrt[\[Pi]] \[Sigma]^2)))/(Sqrt[2] \[Pi]^(
3/4) \[Sigma])
which is different by a factor of
\[Pi]^(1/4)/(Sqrt[2] Gamma[n/2])
I hope that helps indicate where the problem is.
URL: , |
|
