| Author |
Comment/Response |
Michael
|
 07/29/12 10:43am
For your specific question, FTW has a closed-form formula, StepSize * t = t. Plot gives a good picture (as a continuous line though).
StepSize = 1;
Plot[StepSize * t, {t, 0, 200}]
Here are some other ways to do it:
ListPlot[Range[0 StepSize, 200 StepSize, StepSize],
DataRange -> {0, 200}]
ListPlot[Accumulate[Table[StepSize, {t, 0, 200}]],
DataRange -> {0, 200}]
Somehow I wonder if your specific question was a simple example of what you wanted to do. If your step size varies, then here are a couple of ways to plot the accumulation.
step[t_] := 1/(1 + t);
ListPlot[Accumulate[Table[step[t], {t, 0, 200}]],
DataRange -> {0, 200}]
ListPlot[Table[Sum[step[s], {s, 0, t}], {t, 0, 200}],
DataRange -> {0, 200}]
Finally, if you want to plot a function of the accumulated values, here is one way. The first Table below lets x range over the accumulated steps (Accumulate[..]) and passes the points {x, f[x]} to ListPlot to be plotted.
f[x_] := x^2;
ListPlot[Table[{x, f[x]}, {x,
Accumulate[Table[step[t], {t, 0, 200}]]}], DataRange -> {0, 200}]
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