| Author |
Comment/Response |
Manjula
|
 08/15/12 12:08pm
I have tried to use Mathematica on evaluating complete elliptic integral of the first kind by entering:
Integrate[1/Sqrt[1-(r^2 Sin[\[Phi]]^2)/x^2],{\[Phi],0,\[Pi]/2},Assumptions->Re[r^2/x^2]>1&&r^2/x^2\[Element]Reals]
Mathematica has given me the answer:
EllipticK[r^2/(r^2-x^2)]/Sqrt[1-r^2/x^2]
But to me, the correct answer should be
EllipticK[r^2/x^2]
Can you please show me where I have gone wrong?
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