| Author |
Comment/Response |
Amir
|
 08/21/12 09:32am
I think there is a bug in Mathematica 8 for the following integration
Integrate[(1+ a^4 Tan[2x -2y]^2)/(1+ a^2 Tan[2x -2y]^2),{x,0,2Pi},Assumptions-> y\[Element] Reals]
It gives me a solution as (2 Pi a^4/(a^2-1)) which is not correct, if we put a=1 in the integral the answer would be simply 2Pi but mathematica answer is infinite when a=1.
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