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08/21/12 09:32am

I think there is a bug in Mathematica 8 for the following integration

Integrate[(1+ a^4 Tan[2x -2y]^2)/(1+ a^2 Tan[2x -2y]^2),{x,0,2Pi},Assumptions-> y\[Element] Reals]

It gives me a solution as (2 Pi a^4/(a^2-1)) which is not correct, if we put a=1 in the integral the answer would be simply 2Pi but mathematica answer is infinite when a=1.

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Subject (listing for 'Bug in Integration')
Author Date Posted
Bug in Integration Amir 08/21/12 09:32am
Re: Bug in Integration Nasser M. Ab... 08/21/12 11:41am
Re: Bug in Integration jf 08/21/12 1:13pm
Re: Re: Bug in Integration Amir 08/24/12 10:31am
Re: Bug in Integration Peter Pein 08/26/12 5:17pm
Re: Re: Bug in Integration Amir 08/31/12 09:41am
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