| Author |
Comment/Response |
Bill Simpson
|
 02/02/13 11:41pm
Can you apply something like this?
Some made up b values
In[2]:= b=RandomReal[{-2,2},5]
Out[2]= {-1.60966,0.503958,-1.05172,1.00248,-0.911008}
A made up quadratic that uses one b value each time
In[3]:= sols=t/.Map[Solve[2t^2+# t-6==0,t]&,b]
Out[3]= {{-1.37577,2.1806},{-1.86262,1.61064},{-1.48896,2.01482},{-2.00071,1.49947},{-1.51921,1.97471}}
In[4]:= positivesols=DeleteCases[Flatten[sols],t_/;t<0]
Out[4]= {2.1806,1.61064,2.01482,1.49947,1.97471}
Test this carefully before you depend on it. Note that it doesn't let you know if there were zero, one or two positive roots, it just gives you the positive values.
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