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 Author Comment/Response Nigel Eames 10/19/99 11:20am I really would appreciate your help in solving this integral and if it's possible show the solution step by step. I wonder if the integral could be plotted, in order to find a simpler function that closely approximates the given function. The integral is a function of z` and z (butI wanted to hold z constant at first). E=[1+ (1/k^2)(2nd parital diff eq respect to z)]{2 Integral{sin[k(L-z`)] * Exp {jkSqrt[(z-z`)^2 + a^2]} / Sqrt[(z-z`)^2 + a^2]}dz`} The limits are from 0 to L. where, z = L/2 (a try) lamda = 3 meters L = lamda/4 = 0.75 meters a = 0.03 meters k = 2 Pi/lamda E = Electric field in the gap I split the integral into the real and imaginary parts. I attempted to integral the imaginary part first. I used Taylor series to approximate the function for L=0.4. It turns out that a fourth order expansion is a good approximation. Mathematica was able to integral it. It seems unable to differentiate the integral and add to it the original integral. I would really appreciate your help with this difficult problem. I have a copy of Mathematica for students version 3.0.0, license: L2709-1961, running on a Pentium 333MHz with a Windows 98 OS. URL: ,

 Subject (listing for 'Calculating the electric field of a dipole') Author Date Posted Calculating the electric field of a dipole Nigel Eames 10/19/99 11:20am Re: Calculating the electric field of a dipole Fabrice P. L... 11/13/99 07:15am
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