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 Author Comment/Response Pierre 09/10/12 1:33pm In Response To 'Re: Fourier Transform of a Lorentz function'---------Thanks You right, i was expecting a result with {0,2Pi} parameters for signal processing. It works fine now for the 'complex' Lorentzian function: Boltz = 1/(1 + (2*(x-xo)/Dx)^2) TransfBoltz gives: (Pi/2)*Dx*Exp[-Pi*Dx*Abs[X]] And that is what i was expecting. But still, even with {0,2Pi} parameters, the simplest Lorentzian function: Boltz = 1/(1 + x^2) TransBoltz = FourierTransform[Boltz, x, X, FourierParameters -> {0, 2 Pi}] Gives: Pi*Exp[-2Pi*Abs[X]] When theorical Fourier Transform (i've checked it on internet but i'm not 100% sure) should be: Pi*Exp[-Abs[X]] As you see, the Exp slope is very different... And this result cannot be obtained with any parameters... URL: ,

 Subject (listing for 'Fourier Transform of a Lorentz function') Author Date Posted Fourier Transform of a Lorentz function Pierre 09/09/12 4:25pm Re: Fourier Transform of a Lorentz function Bill Simpson 09/09/12 9:22pm Re: Re: Fourier Transform of a Lorentz function Pierre 09/10/12 1:33pm
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