| Author |
Comment/Response |
Pierre
|
 09/10/12 1:33pm
In Response To 'Re: Fourier Transform of a Lorentz function'
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Thanks
You right, i was expecting a result with {0,2Pi} parameters for signal processing.
It works fine now for the 'complex' Lorentzian function: Boltz = 1/(1 + (2*(x-xo)/Dx)^2)
TransfBoltz gives: (Pi/2)*Dx*Exp[-Pi*Dx*Abs[X]]
And that is what i was expecting.
But still, even with {0,2Pi} parameters, the simplest Lorentzian function:
Boltz = 1/(1 + x^2)
TransBoltz =
FourierTransform[Boltz, x, X, FourierParameters -> {0, 2 Pi}]
Gives:
Pi*Exp[-2Pi*Abs[X]]
When theorical Fourier Transform (i've checked it on internet but i'm not 100% sure) should be:
Pi*Exp[-Abs[X]]
As you see, the Exp slope is very different...
And this result cannot be obtained with any parameters...
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