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 Author Comment/Response Nuber Andi 12/21/99 7:42pm Hi, I have 2 Problems and would be happy if s.o. could answer them:1)can Mathematica also solve an inequation if it depends also on a parameter? e.g. InequalitySolve[f\_k[x] < 0, x] when I tried it Mathematica couldn't do it, it worked only with concrete values(e.g. for k=2). 2) How can I define that Mathematica only uses certain values e.g. f\_k[x_]:=(k*x)/(x^2-k^2) with x > 0 or that Solve[Log[-4+x^2]==5,x] with x > 5 gives me only the positive Solution (or the one which fits with the definition set)and not both? Thanks a lot for the answers previously! ANDI URL: ,

 Subject (listing for 'InequalitySolve with parameters and definition of values') Author Date Posted InequalitySolve with parameters and definition ... Nuber Andi 12/21/99 7:42pm Re: InequalitySolve with parameters and definit... Forum Modera... 12/22/99 07:37am
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