Author 
Comment/Response 
Michael

09/16/12 08:19am
There are infinitely many solutions  just what sort of representation are you looking for? One such is the equation
Exp[z] == I
which can be plugged in to Reduce:
In[1]:= Reduce[ Exp[z] == I, {z}]
Out[1]= C[1] \[Element] Integers && z == ((I \[Pi])/2) + 2 I \[Pi] C[1]
Or get all (finite many) solutions in a certain domain:
In[2]:= Reduce[2 \[Pi] < Im[z] < 6 \[Pi] && Exp[z] == I, {z}]
Out[2]= z == (7 I \[Pi])/2  z == (11 I \[Pi])/2
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