| Author |
Comment/Response |
Bill Simpson
|
 09/16/12 10:22am
If you can justify transforming z==Log[-I] into E^z==-I then
In[1]:= Reduce[E^z==-I,z]
Out[1]= C[1] ∈ Integers && z==(-I/2)*Pi+ (2*I)*Pi*C[1]
You might try that on other problems and see how often that will give you what you want. If you have Reduce[z==something,z] that does not usually seem to give you all solutions, you need to make it work a little harder than that.
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