I am just trying to solve:
dy/dx when x = 2t + 5 and y = 2t^2 - 1.
Can it be done directly by Mathematica or do I have to solve dy/dt and dx/dt and finally divide dy/dt by dx/dt?
I tried posing x = 2t + 5 and y = 2t^2 - 1 and ask solve for D [y,x], but that does not evaluate properly (the answer is 2t). I would have thought that Mathematica would have used the chain rule automatically.
Thanks for your help,