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07/24/00 06:44am


I am just trying to solve:
dy/dx when x = 2t + 5 and y = 2t^2 - 1.

Can it be done directly by Mathematica or do I have to solve dy/dt and dx/dt and finally divide dy/dt by dx/dt?

I tried posing x = 2t + 5 and y = 2t^2 - 1 and ask solve for D [y,x], but that does not evaluate properly (the answer is 2t). I would have thought that Mathematica would have used the chain rule automatically.

Thanks for your help,


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