| Author |
Comment/Response |
David Belisle
|
 04/21/97 11:58pm
Reply to message #290 from Robert Spanier: > I am using Mathematica
version 3.0 for > Windows ''95'' > > How do I graph a Conic Section,
such as a Hyperbola, with the following equation y^2-4x^2+4y+24x-41=0
on a Cartesian Coordinate Plane? > > Many Thanks! > Robert > You can
use the ImplicitPlot package: <<Graphics`ImplicitPlot`; ImplicitPlot[y^2-4x^2+4y+24x-41==0,{x,-10,10}]
I hope this helps, Dave
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