Can Mathematica take the derivative of a complex function?
I have a function f(z)=(ln r)^2-t^2+i2t(ln r) where t=theta,
r>0, -pi<t<pi. I have taken the partials and confirmed that the function meets the Cauchy-Riemann conditions and I know its continuous on its domain. So, I know f'(z) exists and I have calculated a value for f'(z). I would now like to confirm my calculation.