| Author |
Comment/Response |
Al Mannon
|
 03/18/01 06:16am
Can Mathematica take the derivative of a complex function?
I have a function f(z)=(ln r)^2-t^2+i2t(ln r) where t=theta,
r>0, -pi<t<pi. I have taken the partials and confirmed that the function meets the Cauchy-Riemann conditions and I know its continuous on its domain. So, I know f'(z) exists and I have calculated a value for f'(z). I would now like to confirm my calculation.
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