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Alexander
04/23/13 00:59am

This is it, thank you!

(I can now clearly see that this formula cannot be used to approximate the derivative at b[n] as the coefficients do not converge backwards.)

Just one further question: In my formula I have the sum signs instead of Sum[] and I'm getting:

Out[2]= Symbol/6 - (6*b[1])/5 + (15*b[2])/4 - (20*b[3])/3 + (15*b[4])/2 - 6*b[5] + (49*b[6])/20

What does that 'Symbol' mean?

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Subject (listing for 'coefficient evaluation')
Author Date Posted
coefficient evaluation Alexander 04/22/13 3:20pm
Re: coefficient evaluation Bill Simpson 04/22/13 4:28pm
Re: coefficient evaluation Alexander 04/23/13 00:59am
Re: Re: coefficient evaluation Bill Simpson 04/23/13 2:12pm
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