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Author Comment/Response
Bill Simpson
05/13/13 12:38pm

I first try your inner integral:

In[1]:= Integrate[r^2 Sin[\[Theta]] E^(-((r - R)^2/b^2))E^(-((r^2 (Cos[\[Theta]])^2)/d^2))E^(-I r q (Cos[\[Theta]] Cos[\[Psi]] + Cos[\[Phi] - \[CurlyPhi]] Sin[\[Theta]] Sin[\[Psi]])), {\[Phi], 0, 2 \[Pi]}, {\[Theta], 0, \[Pi]}, {r, 0, \[Infinity]}]

Out[1]= 0

Then I substitute zero

In[2]:= NIntegrate[Sin[\[Psi]] q^2 q^2/(b^2 q^4 + 1^2)*0, {\[CurlyPhi], 0, 2 \[Pi]}, {\[Psi], 0, \[Pi]}, {q, 0, \[Infinity]}]

Out[2]= 0

Or I see that by just looking at the integral.

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Subject (listing for 'A numerical integration problem')
Author Date Posted
A numerical integration problem Wenle Weng 05/12/13 11:05pm
Re: A numerical integration problem Bill Simpson 05/13/13 12:38pm
Re: Re: A numerical integration problem Wenle Weng 05/16/13 8:55pm
Re: Re: Re: A numerical integration problem Bill Simpson 05/17/13 11:03am
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