| Author |
Comment/Response |
Shue-Cheng CHEN
|
 06/02/97 04:33am
Dear Sirs, If there is an expression x^2 - 2x + 1 + 2 Sin[x] Cos[x]
expr = -------------------------------- x^3 - 3 x^2 + 3 x - 1 How
do I ''cut'' this expression into three parts: x^2 - 2x + 1, 2 Sin[x]
Cos[x], x^3 - 3 x^2 + 3 x - 1 And after I simplify each of them, how
do I ''paste'' them to the original expression, which finally becomes
(x-1)^2 + Sin[2 x] expr = -------------------- (x-1)^3 Mathematica
should have elegant ways to do it. Thank you so much. Best Regards,
Shue-Cheng CHEN
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