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 Author Comment/Response Thibault 07/01/13 08:26am Hello, I am struggling with mathematica 8 to extract polynomial parameters from an equation (did it by hand but i wanted confirmation) the software only returns an input interpretation and not the actual result. I'd be very grateful if someone could help me. Thx for your time input: f = (2^(1/6)/((1 - 2^(1/6))*r))^2; k = f*((3/2) kb*t - H); S = kb*ln[ c*(2*pi*exp (1)/((1/kb*t)*K0))^(3/2)] - (3/ 2)*((-23/12) + (10*k/(3*K0)) - (2*k^2/K0^2) + (2* k^3/(3*K0^3)) - (k^4/(12*K0^4))); S2 = a0 + a1*H + a2*(H^2) + a3*(H^3) + a4*(H^4); sol = Solve[S == S2, {a0, a1, a2, a3, a4}] output: Solve::svars: Equations may not give solutions for all "solve" variables. >> {{a4 -> -(a0/H^4) - a1/H^3 - a2/H^2 - a3/H + (1/( H^4))(-(3/ 2) (-(23/12) + (10 2^(1/3) (-H + (3 kb t)/2))/( 3 (1 - 2^(1/6))^2 K0 r^2) - ( 2 2^(2/3) (-H + (3 kb t)/2)^2)/((1 - 2^(1/6))^4 K0^2 r^4) + ( 4 (-H + (3 kb t)/2)^3)/( 3 (1 - 2^(1/6))^6 K0^3 r^6) - (-H + (3 kb t)/2)^4/( 3 2^(2/3) (1 - 2^(1/6))^8 K0^4 r^8)) + kb ln[2 Sqrt[2] c ((exp kb pi)/(K0 t))^(3/2)])}} URL: ,

 Subject (listing for 'Probleme with solve') Author Date Posted Probleme with solve Thibault 07/01/13 08:26am Re: Probleme with solve jf 07/01/13 5:23pm
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