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 Author Comment/Response Henry Lamb 09/24/03 7:04pm The procedure depends on what you want to put into your diagram. For a single complex number represented as a point, you can do something like this. z=3+4I; ListPlot[{{Re[z],Im[z]}},AxesOrigin->{0,0},PlotRange->{{-5,5},{-5,5}},AspectRatio->Automatic,AxesLabel->{Re,Im}]; For multiple points, you can do it like this. z={3+4I,2-3I}; ListPlot[Transpose[{Re[z],Im[z]}],AxesOrigin->{0,0},...]; If you want to represent complex numbers as vectors, you can try this. <True,AxesOrigin->{0,0},...]; URL: ,

 Subject (listing for 'Argand diagrams in Mathematica') Author Date Posted Argand diagrams in Mathematica Garth 09/20/03 03:49am Re: Argand diagrams in Mathematica Henry Lamb 09/24/03 7:04pm Re: Argand diagrams in Mathematica Patrick D. 07/13/08 12:24pm
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