| Author |
Comment/Response |
Henry Lamb
|
 10/03/03 7:44pm
Here are two ways to define your function.
teht7a[x_]:=Which[
0<=x<1,x(2-x),
1<=x<2,1
2<=x<=4,(4-x)/2
or
teht7a[x_]:
x(2-x)UnitStep[x(1-x)]+
UnitStep[(x-1)(2-x)]+
(4-x)/2 UnitStep[(x-2)(4-x)]
Then you can plot it with
Plot[teht7a[x],{x,0,4}];
URL: , |
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