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 Author Comment/Response Andrew DuBuisson 10/21/04 5:14pm Two problems that I see regarding the lack of solution. First, I dont think that the equation 2*Log[a,x]-Log[a,(x-1)]==Log[a,(x-2)] has a solution. Second, your kinda right about the solve function being inable. Solve works best for polynomial and algebraic equations. It can work with logs and exponents if they can be solved in an algebraic fashion. For instance Solve[1 Log[a,x]-Log[a,(x-1)]==Log[a,(x-2)] Returns the answer x -> 2+(2)^(1/2) While Solve[1. Log[a,x]-Log[a,(x-1)]==Log[a,(x-2)] Returns a message "The equations appear to involve the variables to be solved for in an essentially non-algebraic way." Regarding the second part. Mathematica likes to put things into their basic elements. Input Log[a,x] and it will return Log[x]/Log[a]. Where Log is the natural log of course. Good luck, Andrew URL: ,

 Subject (listing for 'Solving Log Equations') Author Date Posted Solving Log Equations buffer 09/01/04 10:39pm Re: Solving Log Equations Andrew DuBui... 10/21/04 5:14pm Re: Solving Log Equations Paul Stysley 10/27/04 1:46pm Re: Solving Log Equations KENZOU 10/30/04 5:38pm Re: Solving Log Equations yehuda ben-s... 10/31/04 00:23am Re: Solving Log Equations Henry Lamb 10/31/04 11:52pm
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