| Author |
Comment/Response |
Johann Wieser
|
 11/23/04 3:14pm
My problem is a special case of "IntervalIntersection":
My understanding of "Interval[{a,b}]" is the closed Interval: all Real Numbers with a<=x<=b , that means including a and b:
In[4]:=
IntervalMemberQ[Interval[{2, 3}], 2]
IntervalMemberQ[Interval[{2, 3}], 3]
Out[4]=
True
Out[5]=
True
Also Interval[{2, 2}] seems to be an interval:
Out[7]=
Interval[{2, 2}]
In[6]:=
IntervalMemberQ[Interval[{2, 2}], 2]
Out[6]=
True
But now "IntervalIntersection":
In[8]:=
IntervalIntersection[Interval[{2, 3}], Interval[{3, 4}]]
Out[8]=
Interval[]
Why Interval[] (empty set?) and not Interval[{3, 3}] ??
But now the inconsequence:
In[9]:=
IntervalIntersection[Interval[{2, 3.}], Interval[{3, 4}]]
Out[9]=
Interval[{3, 3.}]
In[10]:=
IntervalIntersection[Interval[{2, 3}], Interval[{3., 4}]]
Out[10]=
Interval[{3., 3}]
In[11]:=
IntervalIntersection[Interval[{2, 3.}], Interval[{3., 4}]]
Out[11]=
Interval[{3., 3.}]
What makes different between Integer and Reals in this case?
Johann Wieser
(LicenseID:L4568-4111 , Version: "4.0 for Microsoft Windows (July 16, 1999)" , ReleaseNumber 1)
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