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Dan
11/23/04 9:36pm

I'd like to know the way Mathematica evaluates x^(1/3) because if I have say f[x_]:=x^(1/3) then
for N[f[-9]] I obtain roughly 1.04+1.80i

But obviously this can't be true since it should really be about -2.08. (-2.08*-2.08*-2.08 ~ -8.99, which is what the cubic root should be)

So what does the complex number represent, where does it come from, and how do I evalute x^(1/3) correctly.

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Subject (listing for 'x^1/3')
Author Date Posted
x^1/3 Dan 11/23/04 9:36pm
Re: x^1/3 highegg 11/29/04 2:26pm
Re: x^1/3 Thomas Wacker 11/29/04 2:54pm
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