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 Author Comment/Response Juan J. Ruiz 01/31/05 04:02am Hello: It must be quite easy but I keep wondering why this happens. It is part of a bigger problem that I simplified for clarity. My question is: Why the result of the following evaluation is cero?. It shouldn't!. If you type and evaluate in Mathematica 5.0: a=.; b=.; Simplify[1/Sqrt[(a-b)^2-(b-a)^2],(a > 0) && (b >0) && (a > b)] Notice that the denominator vanishes. The result given by Mathematica is zero!, however if you try: x=.; Simplify[1/Sqrt[(x)^2-(-x)^2],(x > 0)] the result is ComplexInfinity and also gives an error, I like it! but not the first result. Please, what is happening out there! Can I trust Simplify[] and FullSimplify[]? Thanks. URL: ,

 Subject (listing for 'Bad Results when simplfying (?)') Author Date Posted Bad Results when simplfying (?) Juan J. Ruiz 01/31/05 04:02am Re: Bad Results when simplfying (?) yehuda ben-s... 01/31/05 10:08am Re: Bad Results when simplfying (?) Forum Modera... 01/31/05 10:28am
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