| Author |
Comment/Response |
Juan J. Ruiz
|
 01/31/05 04:02am
Hello:
It must be quite easy but I keep wondering why this happens. It is part of a bigger problem that I simplified for clarity.
My question is: Why the result of the following evaluation is cero?. It shouldn't!.
If you type and evaluate in Mathematica 5.0:
a=.;
b=.;
Simplify[1/Sqrt[(a-b)^2-(b-a)^2],(a > 0) && (b >0) && (a > b)]
Notice that the denominator vanishes.
The result given by Mathematica is zero!, however if you try:
x=.;
Simplify[1/Sqrt[(x)^2-(-x)^2],(x > 0)]
the result is ComplexInfinity and also gives an error, I like it! but not the first result.
Please, what is happening out there!
Can I trust Simplify[] and FullSimplify[]?
Thanks.
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