| Author |
Comment/Response |
Lauren
|
 10/11/05 4:57pm
I put into mathmatica
DSolve[{y''[t] - 2y'[t] - 3y[t] == 3t(\[ExponentialE](2t))}, y[t], t]
the result is
\!\({{y[t] -> \(-\(2\/9\)\)\ \((14\ \[ExponentialE] -
12\ \[ExponentialE]\ t + 9\ \[ExponentialE]\ t\^2)\) + \
\[ExponentialE]\^\(-t\)\ C[1] + \[ExponentialE]\^\(3\ t\)\ C[2]}}\)
So basically the problem is it says part of the answer is 14Exp + ..., but it is the exponent of nothing, this answer makes no sense, what is wrong?
Attachment: Untitled-1.nb, URL: , |
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