Student Support Forum: 'Problem using InequalityPlot' topicStudent Support Forum > General > "Problem using InequalityPlot"

 Next Comment > Help | Reply To Topic
 Author Comment/Response Bonny 12/29/05 2:24pm I am trying to plot the following inequalities: a==(-p^2-q)/(-1+q), b==(-2p)/(-1+q), -0.5<=p<=0.5, 0<=q<=1 using the following command in Mathematica: InequalityPlot[a == \(\(-p\^2\) - q\)\/\(\(-1\) + q\) && b == \(-\(\(2\ p\)\/\(\(-1\) + q\)\)\) && \ \(-0.5`\) ≤ p ≤ 0.5` && 0 ≤ q ≤ 1, {a}, {b}] The error message I am getting is: \!\(InequalityPlot::"region" \(\(:\)\(\ \)\) "The region defined by \!\(\(\(a \[Equal] \(\(\(-p\^2\)\) - q\)\/\(\(\(-1\)\) + q\)\)\ \) && \(\(b \[Equal] \(\(-\(\(\(2\\ p\)\/\(\(\(-1\)\) + q\)\)\)\)\)\)\) && \(\ \(\(\(-0.5`\)\) ≤ p ≤ 0.5`\)\) && \(\(0 ≤ q ≤ 1\)\)\) could not be broken \ down into cylinders."\) I am not sure what is going wrong. Can someone please help? Also, is there any other way to accomplish the same task in Mathematica? Thanks, Bonny. URL: ,

 Subject (listing for 'Problem using InequalityPlot') Author Date Posted Problem using InequalityPlot Bonny 12/29/05 2:24pm Re: Problem using InequalityPlot yehuda ben-s... 01/03/06 03:02am
 Next Comment > Help | Reply To Topic