Three dimensional countours
- To: mathgroup at smc.vnet.net
- Subject: [mg2125] Three dimensional countours
- From: Paul Smith <pw_smith at Postoffice.SandyBay.utas.edu.au>
- Date: Wed, 4 Oct 1995 01:55:03 -0400
I am an honours student at the Uni. of Tasmania (Australia). My honours project requires me to plot out a set of countours in order to define a three dimensional surface. An example is as follows: (My/900)^1.5 + (Mx/900)^1.5 = 1.0 This countour can be found for different defining conditions thus simulating a 3D surface. However, as I am a novice mathematica user and the Math's dep. arn't interested in helping me as I am an engineering student, I was wondering if you could start me off in some way. Thanks - Paul.