Re: Inverse????
- To: mathgroup at smc.vnet.net
- Subject: [mg5501] Re: [mg5477] Inverse????
- From: Sherman Reed <Sherman.Reed at worldnet.att.net>
- Date: Sat, 14 Dec 1996 19:26:05 -0500
- Sender: owner-wri-mathgroup at wolfram.com
At 08:15 AM 12/11/96 +0000, you wrote:
>A matrix a={{0,0,1},{0,0,1},{1,1,1}} which is singular in Z_2, but
>Inverse commands gives the "result":
>
>
>Inverse[a,Modulus->2]=
>{{0, 1, 1}, {1, 1, 0}, {1, 0, 0}}.
>
>
>Is anything wrong ?
>
>
>
>Houshou
>
>
I got the same result as you on 2.2.3,
but on 3.0 I recieved the following
Inverse::"sing":
"Matrix \!\({\({0, 0, 1}\), \({0, 0, 1}\),
\({1, 1, 1}\)}\) is singular."
I assume an error in 2.2.3 that has been fixed
in 3.0. Wolfram will probably comment
sherman reed