Re: multiplying sets
- Subject: [mg2969] Re: multiplying sets
- From: Jorma.Virtamo at vtt.fi (Jorma Virtamo)
- Date: 17 Jan 1996 05:11:10 -0600
- Approved: usenet@wri.com
- Distribution: local
- Newsgroups: wri.mathgroup
- Organization: Wolfram Research, Inc.
- Sender: mj at wri.com
Tommi Salminen <titosa at uta.fi> wrote:
>
> I have a problem as follows:
>
> I have a set, for instance: s={{a,b,c},{d,e},{f,g}}, and I would like
> to get a set t, that includes all possible multiplications between
> those three sets {a,b,c}, {d,e} and {f,g}.
>
> Of course, one way would be :
>
> Outer[Times,{a,b,c},{d,e},{f,g}], but I'd like find some kind
> of a more reasonable way to do it, because it would be just a part
> of a larger program. Anyway, it doesn't have to be some elegant way;
> if it works, it's OK.
>
I don't know what is wrong with the Outer. If you define
s1={a,b,c};
s2={d,e};
s3={f,g};
then Outer yields:
Outer[Times,s1,s2,s3] // Flatten
{a d f, a d g, a e f, a e g, b d f, b d g,
b e f, b e g, c d f, c d g, c e f, c e g}
Another way to write the same is for instance:
s3#& /@ s2#& /@ s1 // Flatten
with an identical result:
{a d f, a d g, a e f, a e g, b d f, b d g,
b e f, b e g, c d f, c d g, c e f, c e g}
Whether this is more reasonable way to write the expression
is rather a matter of taste. Personally, I would prefer Outer,
which also seems to be faster. Maybe you want something faster
than Outer?
-- Jorma Virtamo
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