Re: REQ: (a+b)n
- To: mathgroup at smc.vnet.net
- Subject: [mg6376] [mg6376] Re: [mg6358] REQ: (a+b)n
- From: seanross at worldnet.att.net
- Date: Fri, 14 Mar 1997 14:54:26 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Gerard Wisse wrote:
>
> Hi All,
>
> Who could help me and give the formule of the following:
>
> (a+b)2 = 1a2 + 2ab + 1b2
>
> What is the formule of (a+b)n ???
> n is a variable number.
>
> Thanx!!!
>
> Yiorgos Wisse
> Gerard.Wisse at nlehvfm1.origin.nl
Your e-mail got a little garbled. I am assuming you want the equation
for (a+b)^n. There is no general formula for arbitrary n, but for
n=integer, this is called the binomial expansion. You can find the
formula in any standard mathematical handbook like the CRC mathematical
tables. I believe the formula is
(a+b)^n=Sum[(n-i)!/n! a^i b^(n-i),{i,0,n}]
But you'd better check me on that since I don't have my copy of CRC in
front of me right now.