Re: REQ: (a+b)n
- To: mathgroup at smc.vnet.net
- Subject: [mg6376] [mg6376] Re: [mg6358] REQ: (a+b)n
- From: seanross at worldnet.att.net
- Date: Fri, 14 Mar 1997 14:54:26 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Gerard Wisse wrote: > > Hi All, > > Who could help me and give the formule of the following: > > (a+b)2 = 1a2 + 2ab + 1b2 > > What is the formule of (a+b)n ??? > n is a variable number. > > Thanx!!! > > Yiorgos Wisse > Gerard.Wisse at nlehvfm1.origin.nl Your e-mail got a little garbled. I am assuming you want the equation for (a+b)^n. There is no general formula for arbitrary n, but for n=integer, this is called the binomial expansion. You can find the formula in any standard mathematical handbook like the CRC mathematical tables. I believe the formula is (a+b)^n=Sum[(n-i)!/n! a^i b^(n-i),{i,0,n}] But you'd better check me on that since I don't have my copy of CRC in front of me right now.