Using Sqrt[x_]/y_ ->

• To: mathgroup at smc.vnet.net
• Subject: [mg7314] Using Sqrt[x_]/y_ ->
• From: sergio at scisun.sci.ccny.cuny.edu (Sergio Rojas)
• Date: Fri, 23 May 1997 01:41:48 -0400 (EDT)
• Organization: City College Of New York - Science
• Sender: owner-wri-mathgroup at wolfram.com

```(*--> Hello folks,   *)
(*--->   In Mathematica 2.2, using:  *)

Needs["Calculus`DSolve`"]

answer = DSolve[{(x +e*f[x])*f'[x] + f[x] == 1, f[1]==2}, f[x],x]

f1[x_] =  Expand[f[x] /. answer[[1]]] /. Sqrt[x_]/y_ ->  Sqrt[Expand[x/y^2]]

(*--->   one can get:  *)

(*-----------------------------------------------------------
2            2
x         2 e + 4 e  + 2 e x + x
Out[36]= -(-) - Sqrt[-----------------------]
e                    2
e
------------------------------------------------------------*)

(*---> 1.- How can one use := instead of = in the f1[x_] definition *)
(*---> 2.- Why Expand does not work inside Sqrt[...]                *)

Sergio Rojas
E-mail: sergio at scisun.sci.ccny.cuny.edu

```

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