Re: 1+Cos[x]Cosh[x]==0 ?
- To: mathgroup@smc.vnet.net
- Subject: [mg12148] Re: [mg12109] 1+Cos[x]Cosh[x]==0 ?
- From: "Sherman.Reed" <sherman.reed@worldnet.att.net>
- Date: Mon, 27 Apr 1998 01:46:31 -0400
Eddy,
I plotted the equation 1+(Cos[x])*(Cosh[x]) to get approx values of the
roots. I found xapprox to be {2,4.5,8,11,14,17}.
I then used FindRoot[1+(Cos[x])*(Cosh[x]) ==0,{x,xapprox}] to get good
values of the root.
Sherman C. Reed
sherman.reed@worldnet.att.net
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> From: Eddy Wibowo <ew4516@bristol.ac.uk>
To: mathgroup@smc.vnet.net
> To: mathgroup@smc.vnet.net
> Subject: [mg12148] [mg12109] 1+Cos[x]Cosh[x]==0 ?
> Date: Saturday, April 25, 1998 12:30 AM
>
> Hi everybody,
>
> How to solve "1 + Cos[x] Cosh[x] == 0"? I will probably need just the
> first five, positive solution of "x".
>
> Many thanks before hand.
>
> -Eddy
>