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Re: Find limit of series using Mathematica 2.0

• To: mathgroup@smc.vnet.net
• Subject: [mg12456] Re: [mg12393] Find limit of series using Mathematica 2.0
• From: Sean Ross <seanross@worldnet.att.net>
• Date: Tue, 19 May 1998 13:31:25 -0400
• References: <199805141515.LAA03821@smc.vnet.net.>

Cheung Wai Yuen wrote:
> 
> I am a user of Mathematica 2.0. I do not know how to find the limit of
> series like :
> 1+ 1/2 + 1/4 + 1/16 + ..... . Please tell me the commands in doing so.


Simplify[Sum[1/2^n,{n,1,Infinity}]]

returns

1


I have used this same syntax for other series as well.  One other
example is a partial sum of a geometric progression:

Simplify[Sum[a^n,{n,1,N}]]

returns

a (a^N-1)/(a-1).

I hope that this works in Mathematica 2.0.  I use version 3.0.1.  If you
have the funds, I recommend the upgrade.

• References:
  • Find limit of series using Mathematica 2.0
    • From: Cheung Wai Yuen <cwy1@netvigator.com>