Z-Transform
- To: mathgroup at smc.vnet.net
- Subject: [mg21069] Z-Transform
- From: angela.faessler at isg.ch (Angela Faessler)
- Date: Sun, 12 Dec 1999 23:51:33 -0500 (EST)
- Organization: The Math Forum
- Sender: owner-wri-mathgroup at wolfram.com
Hello How can I get the solution of InverseZTransform[(z^2+z)/(z^2-6z+13),z,k] into its form with trigonometric functions instead of a complex expression? Thanks for an answer! Angela Faessler