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Re: Integrate[1/2+1/2 Erf[z],{z,-inf,0}]

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  • Subject: [mg21088] Re: Integrate[1/2+1/2 Erf[z],{z,-inf,0}]
  • From: "Stephen P Luttrell" <luttrell at>
  • Date: Sun, 12 Dec 1999 23:51:55 -0500 (EST)
  • Organization: Defence Evaluation and Research Agency
  • References: <5jf25g$> <7h7sn4$>
  • Sender: owner-wri-mathgroup at

Hendrik van Hees <h.vanhees at> wrote in message
news:7h7sn4$kmv at
> This is really a problem Mathematica seems not to be able to solve. The
> problem is that it fails to calculate the limit
> inf(1-erf(inf)) for inf->Infinity.
> Doing this from hand with help of de L'Hospital's rule gives clearly 0.
> Although I used Analytic->True within the Limit-command it didn't apply
> this rule.

You need to use the Calculus`Limit` package.


In[2]:=Limit[x(1-Erf[x]),x->Infinity ]


Stephen P Luttrell
DERA Malvern

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