Re: Help! How to execute line integral, surface integral or integration around contour.
- To: mathgroup at smc.vnet.net
- Subject: [mg21216] Re: Help! How to execute line integral, surface integral or integration around contour.
- From: phbrf at t-online.de (Peter Breitfeld)
- Date: Fri, 17 Dec 1999 01:29:16 -0500 (EST)
- References: <7hgdpv$4ck@smc.vnet.net> <832045$gfu@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Stephen P Luttrell <luttrell at signal.dra.hmg.gb> schrieb:
[*** snipp ***]
>
> In[1]:=Integrate[1/z,{z,1,I,-1,-I,1}]
>
> Out[1]=2 I \[Pi]
>
> The {z,1,I,-1,-I,1} specifies a diamond-shaped contour in the complex z
> plane that encloses the pole in 1/z at the origin.
>
This works with NIntegrate only. Integrate gives 0. Or do I miss something?
Gruss Peter
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