Re: How to construct all possible orderings
- To: mathgroup at smc.vnet.net
- Subject: [mg15675] Re: [mg15588] How to construct all possible orderings
- From: Robert Pratt <rpratt at math.unc.edu>
- Date: Sat, 30 Jan 1999 04:29:06 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Flatten[Table[{i,j,k},{i,3},{j,3},{k,3}],2]/.{1->A,2->B,3->C}
will give you
{{A, A, A}, {A, A, B}, {A, A, C}, {A, B, A}, {A, B, B}, {A, B, C},
> {A, C, A}, {A, C, B}, {A, C, C}, {B, A, A}, {B, A, B}, {B, A, C},
> {B, B, A}, {B, B, B}, {B, B, C}, {B, C, A}, {B, C, B}, {B, C, C},
> {C, A, A}, {C, A, B}, {C, A, C}, {C, B, A}, {C, B, B}, {C, B, C},
> {C, C, A}, {C, C, B}, {C, C, C}}
Rob Pratt
Department of Mathematics
The University of North Carolina at Chapel Hill CB# 3250, 331 Phillips
Hall
Chapel Hill, NC 27599-3250
rpratt at math.unc.edu
http://www.math.unc.edu/Grads/rpratt/
On Thu, 28 Jan 1999, Carlos Carreto wrote:
> Hello,
>
> I am trying to construct all possible orderings of for example 3
> elements, where each element can be A, B or C.
>
> The result will be something like this: AAA
> AAB
> AAC
> ABA
> . . .
> CCC
>
> How can I do this?
>
> Thank you.
>
> -:- Carlos
>
>
>
>