MathGroup Archive 1999

[Date Index] [Thread Index] [Author Index]

Search the Archive

Re: col-vector * row-vector = matrix, how ?

  • To: mathgroup at smc.vnet.net
  • Subject: [mg18513] Re: [mg18451] col-vector * row-vector = matrix, how ?
  • From: "Andrzej Kozlowski" <andrzej at tuins.ac.jp>
  • Date: Thu, 8 Jul 1999 22:32:51 -0400
  • Sender: owner-wri-mathgroup at wolfram.com

Do you mean something like this:

In[37]:=
(m = {a, b, c}*v /. v -> {x, y, z}) // MatrixForm
Out[37]//MatrixForm=
a x   a y   a z

b x   b y   b z

c x   c y   c z

?
--
Andrzej Kozlowski
Toyama International University
JAPAN
http://sigma.tuins.ac.jp
http://eri2.tuins.ac.jp


----------
>From: malte.lance at gmx.net (Malte Lance)
To: mathgroup at smc.vnet.net
>To: mathgroup at smc.vnet.net
>Subject: [mg18513] [mg18451] col-vector * row-vector = matrix, how ?
>Date: Wed, Jul 7, 1999, 1:11 PM
>

> Need to know how to accomplish the following in Mathematica-3.0:
>
> v1 := transpose(<a,b,c>)   /* column-vector */
>
> v2 := <x,y,z>              /* row-vector */
>
> ( ax ay az )
> ( bx by bz ) = v1 * v2 =: m /* 3x3-matrix */
> ( cx cy cz )
>
> Does anyone know how to do this in Mathematica ?
>
> Any help is highly appreciated.
> Thanks in advance.
>
> Malte.
>
> --
> Malte Lance.
> --- composed with knews


  • Prev by Date: Re: Q: ReplaceAll with pattern in pattern
  • Next by Date: Re: trouble with printing
  • Previous by thread: Re: col-vector * row-vector = matrix, how ?
  • Next by thread: Re: col-vector * row-vector = matrix, how ?