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Re: Re: A little problem with positive numbers

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  • Subject: [mg18150] Re: [mg18088] Re: A little problem with positive numbers
  • From: BobHanlon at
  • Date: Fri, 18 Jun 1999 00:51:48 -0400
  • Sender: owner-wri-mathgroup at


I'm running v4; however, I think this will give the same result in v3.

Integrate[E^(-v^2/vth^2), {v, -Infinity, +Infinity}, Assumptions -> {vth > 0}]


Bob Hanlon

In a message dated 6/17/99 4:42:11 PM, nicola at writes:

>On Mon, 14 Jun 1999, Murray Eisenberg wrote:
>> What, exactly, are you trying to do?  And what version of Mathematica?
>> The new Version 4 "Support for assumptions in Simplify, FunctionExpand
>> and related functions" may do what you need.
>Really im using version 3.
>Im tryng to calculate something like
>(in my case is a bit more complex but the problem
>is the same):
>and i obtai a complex result:
>I would like to communicate to Math that
>im sure vth is a positive number.
>Bye and thank you for any help

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