Re: REDUCE vs. a symoblic function
- To: mathgroup at smc.vnet.net
- Subject: [mg18273] Re: REDUCE vs. a symoblic function
- From: Jens-Peer Kuska <kuska at informatik.uni-leipzig.de>
- Date: Fri, 25 Jun 1999 15:05:20 -0400
- Organization: Universitaet Leipzig
- References: <7kttal$95n@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi Jerry, Mathematica should get the same result in all 4 cases ? Realy ? I get in the last two cases for F==Sin or F==Cos q== 2Pi n and any a and any interger n, but that is not a solution for the first two. Can you explain why the result for any F should be the same ? Regards Jens > When I type in: > Reduce[a*q - a ==0,a} > OR > Reduce[a*q - a ==0,q] > I get the result: a == 0 OR q == 1 > However, if I type in: > Reduce[ F[a*q] - F[a] == 0,a] I just get back Reduce[ > F[a*q] - F[a] == 0,a] > and if I type in: > Reduce[ F[a*q] - F[a] == 0,q] I get back > a NOT == 0 && q == 1 > Why the difference in these outcomes? These questions were, > in part, motivated by the statement "As well as treating variables like x > symbolically, you can also treat functions , like f[x], in Mathematica > symbolically.....without specifying any explicit form for the function > f[x]." Secondly, assuming that Mathematica doesnt get the result rather > then I didnt use the correct commands to get them, and even if you can > explain why it didnt, should it have gotten the same result in all 4 cases? > > Thanks. Jerry Blimbaum NSWC Panama City, Fl