Re: Finding lengths of identical sequences in lists
- To: mathgroup at smc.vnet.net
- Subject: [mg20270] Re: [mg20240] Finding lengths of identical sequences in lists
- From: Maris Tonso <maris at tpu.ee>
- Date: Sun, 10 Oct 1999 01:27:28 -0400
- References: <199910082230.SAA04776@smc.vnet.net.>
- Sender: owner-wri-mathgroup at wolfram.com
Hope this helps:
A = {3,2,2,3,3,3,1};
Length /@ Split[A]
Maris Tonso
Joel Cannon wrote:
> I am looking for a more elegant solution to the following. I have a
> list (a list of positions at consecutive times). I wish to create a
> new list of the length of each sequence of consecutive identical
> members (including those of length 1).
>
> For example, for the list {3,2,2,3,3,3,1} I would create the list
> {1,2,3,1} because the first 3 appears once, followed by two 2's,
> etc. The lists I was working with contained a list of numbers
> (e.g. {{x1,y1},{x2,y2},...} rather than simple numbers. I accomplished
> this using a while loop, but I suspect there are better ways to do
> this using pattern matching or other approaches.
>
> Thanks much.
>
> ------------------------------------------------------------------------------
> Joel W. Cannon | (724)223-6146
> Dept. of Physics |
> Washington and Jefferson College |
> Washington, PA 15301 |
>
>
- References:
- Finding lengths of identical sequences in lists
- From: Joel Cannon <jcannon@jcannon.washjeff.edu>
- Finding lengths of identical sequences in lists