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Re: Re: how to avoid numeric error

  • To: mathgroup at
  • Subject: [mg20520] Re: [mg20397] Re: [mg20309] how to avoid numeric error
  • From: BobHanlon at
  • Date: Wed, 27 Oct 1999 02:05:11 -0400
  • Sender: owner-wri-mathgroup at


Without knowing how they implement Power for integer and non-integer powers, 
I would guess that the answer is related to

(-5.2)^1208. == Exp[1208. * Log[-5.2]]


(-5.2)^1208 == (Times @@ Table[-5.2, {1208}])


Bob Hanlon

In a message dated 10/26/1999 8:23:17 AM, atulksharma at writes:

>Thanks for the comment and function. I still am not clear on why the
>floating point x1 doesn't force machine precision, regardless of whether
>exponent is a float or integer, since I had thought that even one floating
>point parameter results in the entire expression being evaluated

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