Re: Selecting numbers with all odd digits
- To: mathgroup at smc.vnet.net
- Subject: [mg22199] Re: [mg22170] Selecting numbers with all odd digits
- From: Andrzej Kozlowski <andrzej at platon.c.u-tokyo.ac.jp>
- Date: Fri, 18 Feb 2000 02:34:35 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
on 00.2.17 3:23 PM, Tom De Vries at tdevries at shop.westworld.ca wrote:
> Hello all,
>
> In one of the math classes I am teaching we are doing some work with
> permutations and combinations. One question in the text was, "how many
> positive integers less than 700 have all odd digits?"
>
> I had done the question "by hand" and then wondered how to use Mathematica
> to demonstrate that the solution was the correct one.
>
> I am still very far down on the learning curve in most things, but I managed
> to bludgeon my way to an answer (thankfully the same as mine!)
>
> Select[
>
> Range[699],
>
> Union[ OddQ [ IntegerDigits[#]]] == {True} &
>
> ]
>
> I am sure my trial and error method can be improved upon. I am not talking
> speed as much as simply using Mathematica in a way that makes sense and
> would be more logical??
>
> Thanks for any suggestions might have!
>
> Tom De Vries
> Edmonton, Alberta
> Canada
>
>
Your code is basically fine. The following seems to me just a little bit
more natural and also somewhat faster:
In[5]:=
Select[ Range[10^5], And @@ OddQ [ IntegerDigits[#]] == True & ]; // Timing
Out[5]=
{13.7167 Second, Null}
In[6]:=
Select[Range[10^5], Union[ OddQ [ IntegerDigits[#]]] == {True} & ]; //
Timing
Out[6]=
{23.7 Second, Null}
--
Andrzej Kozlowski
Toyama International University
Toyama, Japan
http://sigma.tuins.ac.jp/