Antwort: Simplifying things
- To: mathgroup at smc.vnet.net
- Subject: [mg26078] Antwort: [mg26070] Simplifying things
- From: Adalbert Hanssen <hanssen at Zeiss.de>
- Date: Tue, 28 Nov 2000 01:55:26 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Hi, try this:
expr=(1+Sqrt[(a-1)^2])^5+(1+1/Sqrt[(b-1)^2])^3;
Clear[x];
expr//. {(Sqrt[x_^2])->x, (1/Sqrt[x_^2])->1/x}
it gives
a^5 + (1 + (-1 + b)^(-1))^3
Note:
1.) Don't forget the parentheses around Sqrt in the
replacement rules.
2.) Usually, you need two rules, one for the numerator,
another one for a denominator, due to the different
internal representation of 1/Sqrt[x].
regards
Adalbert
djago at my-deja.com
22.11.00 08:23
An: mathgroup at smc.vnet.net@EMAIL
Kopie: (Blindkopie: Adalbert Hanssen/Aalen/Zeiss/DE)
Thema: [mg26070] Simplifying things
Hi!
I need to simplify looooong equations, but don't know how to get rid of
those terms like:
Sqrt[a^2]
when a is a real positive variable... How can I tell Mathematica 3 to
simplify this?
Thanks!
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