solve f(x)=0, where f:Rn+1 -> Rn
- To: mathgroup at smc.vnet.net
- Subject: [mg26189] solve f(x)=0, where f:Rn+1 -> Rn
- From: Pavel.Pokorny at vscht.cz
- Date: Thu, 30 Nov 2000 22:02:08 -0500 (EST)
- Organization: Prague Institute of Chemical Technology
- Sender: owner-wri-mathgroup at wolfram.com
Dear Mathematica friends
Is there a way in Mathematica 4.0 to solve (numerically) the problem
f(x) = 0
where f: R^{n+1} -> R^n,
i.e. f has n+1 real arguments and n real results ?
The solution is (under certain conditions on f)
a curve in (n+1)-dim space.
Example
x^2 + y^2 - 1 = 0
is a unit circle.
This problem is called "continuation" in nonlinear system analysis
see
Seydel: Tutorial on Continuation
Int.J.Bif.Chaos, Vol.1 No.1 (1991) pp 3-11.
--
Pavel Pokorny
Math Dept, Prague Institute of Chemical Technology
http://staff.vscht.cz/mat/Pavel.Pokorny