Re: PolarPlot question
- To: mathgroup at smc.vnet.net
- Subject: [mg25057] Re: PolarPlot question
- From: "Borut L." <JustMyName at email.si>
- Date: Thu, 7 Sep 2000 22:28:00 -0400 (EDT)
- References: <8ov0jn$9p8@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Hi,
<<Graphics`Graphics`
r[fi_]:=16/(5+3 Cos[fi])
PolarPlot[r[fi],{fi,0,2 Pi}]
it works for me.
Doug Magnoli <dmagnoli at home.com> wrote in message
news:8ov0jn$9p8 at smc.vnet.net...
> I've defined:
>
> r[t] := 16/(5 + 3 Cos[t])
>
> Then I load Graphics, with:
>
> <<Graphics`
>
> and ask for: