RE: powersum with a function with variable count of parameters
- To: mathgroup at smc.vnet.net
- Subject: [mg25280] RE: [mg25262] powersum with a function with variable count of parameters
- From: "David Park" <djmp at earthlink.net>
- Date: Tue, 19 Sep 2000 03:45:07 -0400 (EDT)
- Sender: owner-wri-mathgroup at wolfram.com
Peter,
Map powers of 10 onto the arguments and then apply Plus.
powersum[args__] := Plus @@ (10^# &) /@ {args}
powersum[1, 2, 3]
1110
David Park
djmp at earthlink.net
http://home.earthlink.net/~djmp/
> -----Original Message-----
> From: Klamser [mailto:Klamser at t-online.de]
To: mathgroup at smc.vnet.net
> Hi,
>
> how can I write a function f[x_,xi__]=10^x+10^xi, that returns
> f[1,2,3]->10^1+10^2+10 ^3.
>
> When i use the above definition, I only get
>
> 10^1+10^2^3
>
> But I want to get
>
> 10^1+10^2+10 ^3
>
> Regrads, Peter