Re: Solve InterpolatingFunction problem
- To: mathgroup at smc.vnet.net
- Subject: [mg31881] Re: Solve InterpolatingFunction problem
- From: bghiggins at ucdavis.edu (Brian Higgins)
- Date: Sun, 9 Dec 2001 06:07:04 -0500 (EST)
- References: <9uss9d$cl6$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Jasem" use FindRoot instead of Solve . For example
mySin = Interpolation[Table[{x, Sin[x]}, {x, 0, 5, .2}]];
In[4]:=FindRoot[mySin[x] == .5, {x, 1}]
Out[4]={x -> 0.523618}
Cheers,
Brian
"Jasem Mutlaq" <mutlaqja at ku.edu> wrote in message news:<9uss9d$cl6$1 at smc.vnet.net>...
> Hello. I obtained an interpolated function from a set of data representing a
> velocity curve (increasing & decreasing). I used the following
>
> vr =Interpolation[data];
> Solve[vr[x]==0.6,x]
>
> InverseFunction::ifun: Inverse functions are being used. Values may be lost
> for multivalued inverses.
> Out[221]={{x->1.
> InverseFunction[InterpolatingFunction[{{0.,0.95}},<>],1,1][0.6]}}
> I'm expecting something like x = 3 or x = 9 (two solutions).
>
> Any suggestions are highly appreciated!
>
> Jasem Mutlaq.