Re: Very simple limit, why doesn't it evaluate?
- To: mathgroup at smc.vnet.net
- Subject: [mg31924] Re: Very simple limit, why doesn't it evaluate?
- From: "Allan Hayes" <hay at haystack.demon.co.uk>
- Date: Wed, 12 Dec 2001 04:14:06 -0500 (EST)
- References: <9v49pp$n1v$1@smc.vnet.net>
- Sender: owner-wri-mathgroup at wolfram.com
Jacek,
We can extend the Limit function by using one of the standard packages that
come with Mathematica.
Load the package
<<Calculus`Limit`
Now we get
Limit[4^(n+3)/(3^(n+4)-5),n->Infinity+I]
Infinity
--
Allan
---------------------
Allan Hayes
Mathematica Training and Consulting
Leicester UK
www.haystack.demon.co.uk
hay at haystack.demon.co.uk
Voice: +44 (0)116 271 4198
Fax: +44 (0)870 164 0565
"Jacek Dziedzic" <dust-NOSPAM- at tenbit.pl> wrote in message
news:9v49pp$n1v$1 at smc.vnet.net...
> It stunned me that the Mathematica 3.0 returns this very simple limit
> unevaluated:
> 4^(n+3)/(3^(n+4)-5), with n -> infinity.
>
> Moreover, the NLimit function returns 1.0756... which is a rather poor
> approximation of infinity (the expected result)... Well I can understand
> that NLimit is numerical and can't be relied on, but why does the original
> Limit[] die on that? Or am I doing anything wrong?
>
> - Jacek Dziedzic
>
>
>