Re: Re: Random Sampling Without Replacement?
- To: mathgroup at smc.vnet.net
- Subject: [mg26639] Re: [mg26608] Re: [mg26586] Random Sampling Without Replacement?
- From: "Richard Finley" <rfinley at medicine.umsmed.edu>
- Date: Sat, 13 Jan 2001 22:36:16 -0500 (EST)
- Sender: owner-wri-mathgroup at wolfram.com
Tomas,
You are right about the package name...I just did it from memory and didn't check. But for the question, remember that it concerned drawing from a list of integers 1 to N which your example is not. For the problem as specified it works OK. RF.
>>> Tomas Garza <tgarza01 at prodigy.net.mx> 01/11/01 01:20PM >>>
I think there is an error in your suggestion (apart from the fact that the
package is called DiscreteMath` - not DiscreteMathematics`). See, if the
original list from which the samples are to be taken is e.g. {2, 4, 6, 8,
10, 12, 14, 16, 18, 20}, with size 10, then
In[1]:=
Take[RandomPermutation[10], 3]
Out[1]=
{1, 9, 10}
and here you obtain two elements (1 and 9) who do not belong to the original
list. Check, e.g., [mg26602] .
Tomas Garza
Mexico City
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